Quantitative Literacy Practice Exam 2026 – Comprehensive Preparation Guide

Question: 1 / 400

What is the perimeter of a picture enlarged by 80% if the original dimensions are 24 inches by 36 inches?

180 inches

200 inches

216 inches

To find the perimeter of the enlarged picture, we first need to calculate the new dimensions after the enlargement. The original dimensions of the picture are 24 inches by 36 inches.

To enlarge the picture by 80%, we increase each dimension by 80% of its current length.

First, let's calculate the increase for each dimension:

For the width:

- 80% of 24 inches is 0.80 × 24 = 19.2 inches.

- The new width will be the original width plus this increase: 24 inches + 19.2 inches = 43.2 inches.

For the height:

- 80% of 36 inches is 0.80 × 36 = 28.8 inches.

- The new height will be the original height plus this increase: 36 inches + 28.8 inches = 64.8 inches.

Now, we can calculate the perimeter of the enlarged picture. The formula for the perimeter (P) of a rectangle is:

P = 2 × (length + width)

Substituting the new measurements into the formula:

P = 2 × (43.2 inches + 64.8 inches)

P = 2 × 108

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