Quantitative Literacy Practice Exam 2025 – Comprehensive Preparation Guide

To determine the correct probability of drawing a green marble followed by an orange marble without replacement, we can break the problem into two parts.

First, we need to find the probability of drawing a green marble from the bag. There is 1 green marble out of a total of 10 marbles. Thus, the probability of drawing a green marble is calculated as:

\[ P(\text{Green}) = \frac{1}{10} \]

Once the green marble is drawn, it is not replaced in the bag. This leaves us with a total of 9 marbles remaining, including the original 3 orange marbles.

Next, we find the probability of drawing one of the orange marbles now that we've already removed a green marble. The probability of drawing an orange marble from the remaining 9 marbles is:

\[ P(\text{Orange | Green}) = \frac{3}{9} = \frac{1}{3} \]

To find the overall probability of both events happening in sequence (drawing a green marble first and then an orange marble), we need to multiply the probabilities of these two independent events together:

\[ P(\text{Green and then Orange}) = P(\text{Green}) \times P